0.6=2v^2

Solution for 0.6=2v^2 equation:

0.6=2v^2

We move all terms to the left:

0.6-(2v^2)=0

a = -2; b = 0; c = +0.6;
Δ = b2-4ac
Δ = 02-4·(-2)·0.6
Δ = 4.8
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{4.8}}{2*-2}=\frac{0-\sqrt{4.8}}{-4}
=-\frac{\sqrt{}}{-4}
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{4.8}}{2*-2}=\frac{0+\sqrt{4.8}}{-4}
=\frac{\sqrt{}}{-4}
$